1) 2) 3) 4) 5) 6) 7) 8) multi choice line of charge with linear density lambda1
ID: 2134344 • Letter: 1
Question
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line of charge with linear density lambda1 = -7.9 uC/m is positioned along the axis of a thick conducting shell of inner radius a = 2.8 cm and outer radius b = 5.1 cm and infinite length. The conducting shell is uniformly charged with a linear charge density lambda 2 = 4 uC/m. What is Ex(P), the electric field at point P, located at (x,y) = (-7.6 cm, 0 cm) ? What is Ey(P), the electric field at point P, located at (x,y) = (-7.6 cm, 0 cm) ? What is Ex(R), the electric field at point R, located a distance dR = 1.2 cm from the origin and making an angle of 30degrees with respect to the y-axis as shown? What is Ey(R), the electric field at point R, located a distance dR = 1.2 cm from the origin and making an angle of 3odegrees with respect to the y-axis as shown? What is ?b, the linear charge density on the outer surface of the conducting shell ? What is lambda(a) the linear charge density on the inner surface of the conducting shell ? The charged conducting shell is now replaced by an uncharged conducting shell of the same dimensions. What is ?b, the linear charge density on the outer surface of the uncharged conducting shell ? multi choice The conducting shell is now given a new charge (lambda2,new uC/cm) such that the electric field at point P becomes equal to 0. What must be the sign of lambda(b), the linear charge density on the outer surface of the charged conducting shell? Lambda(b) (less than) 0 lambda(b) = 0 lambda(b) (greater than) 0Explanation / Answer
1)
Ex(p) =(lambda1+lambda2)/2pieox
Ex(p) =(-7.9+4)*10^-6/2pi*8.85*10^-12*(-0.076)
Ex(p) =922,843.11 N/C
2)
due to radial symmetry the electric field through any line through the origin is anti parallel to that line.
Ey(p) =0 N/C
3)
Ex(R) =lambda1*sin(theta)/2pieodR
Ex(R)=-(7.9*10^-6)sin(30)/2pi*8.85*10^-12*0.012
Ex(R) =-5,919,604.757 N/C
4)
Ey(R) =-lambda1*cos(theta)/2pieodR
Ey(R)=(7.9*10^-6)cos(30)/2pi*8.85*10^-12*0.012
Ey(R)=10,253,056.2 N/C
5)
lambda_b =lambda1+lambda2 =-3.9 uC/m
6)
lambda_a =-lambda1 =7.9uC/m
7)
lambda_b =-7.9uC/m
8)
lambda_b=0
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