Okay, so the situation is that we have a cube of ice taken from freezer at -8.7

Question

Okay, so the situation is that we have a cube of ice taken from freezer at -8.7 C and placed in 91 g aluminum calorimeter filled with 317 g water at room temperature at 20 C. Final solution is observed to be all water at 17 C. Solve for mass of ice cube in kilograms.

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Okay, so the situation is that we have a cube of ice taken from freezer at -8.7 C and placed in 91 g aluminum calorimeter filled with 317 g water at room temperature at 20 C. Final solution is observed to be all water at 17 C. Solve for mass of ice cube in kilograms.

Thank you! Will rate!

Explanation / Answer

m be mass of ice

Heat for melting ice= (m*2.09*8.7 + m*334)= m* 352.183 J

Heat required to raise temperature of melted ice= m*4.18*17=m* 71.06 J

Total heat absorbed= m* 423.243 J

Heat lost by aluminium= 91*0.91*(20-17)= 248.43 J

Heat lost by calorimeter water= 317*4.18*(20-17)= 3975.18J

Total heat lost= 4223.61 J

mass of ice=m= 9.979 grams

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