please show ur work to get credit, am sick. At the airport, you pull a 17 kg sui
ID: 2133270 • Letter: P
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please show ur work to get credit, am sick.
At the airport, you pull a 17 kg suitcase across the floor at constant velocity with a strap that is at an angle of 41° above the horizontal. Find the normal force on the suitcase, given that the coefficient of kinetic friction between the suitcase and the floor is 0.32. N Find the tension in the string between m1 and m2 in the following figure, given that m1 = 1.2 kg, m2 = 1.5 kg, and m3 = 3.2 kg. N The system shown in the following figure is in static equilibrium and the angle theta = 32°. Given that the mass m1 is 8.40 kg and the coefficient of static friction between mass m1 and the surface on which it rests is 0.310, what is the minimum mass that m2 can have for which the system will still remain in equilibrium? kg Two known forces Fj1= 3.6 N at 77degree below the +x axis and F2 = 3.6 N at 38degree above the -x axis are acting on an object, (a) What is the magnitude of the third force F3 so that the acceleartion of the object is zero? N In serving, a tennis player accelerates a 57-gram tennis ball horizontally from rest to a speed of 30 m/s. Assuming the acceleration is uniform when the racquet applies a forceExplanation / Answer
5) sum forces in the x:
F*cos(41) - u N = 0
f = uN/cos(41)
sum forces in the y:
F*sin(41) + N - mg = 0
0.32*N*tan(41) + N - 17*9.81=0
N=130.48 N
6)
m3g = (m1 + m2 + m3) a
a = 3.2*9.81/(3.2+1.5+1.2)=5.32 m/s^2
for block m1
T = m1 a = 1.2*5.32=6.38 N
7) min mass m2 so it will be going down the slope
m1 g sin theta - m2g - friction = (m1 + m2)*0
friction = u m1 g cos theta
8.4*sin(32) - m2 - 0.31*8.4*cos(32)=0
m2 = -0.31*8.4*cos(32) + 8.4*sin(32)=2.24 kg
8)
F3x = -F1x - F2x = -3.6*cos(77) - 3.6*cos(38)=-3.65 N
F3y = -3.6*sin(77) -3.6*sin(38)=-5.72
so F3 = sqrt(3.65^2 + 5.72^2)=6.79 N
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