-This question has two parts The diagram below shows a dipole centered at the or
ID: 2133194 • Letter: #
Question
-This question has two parts
The diagram below shows a dipole centered at the origin and along the x-axis. Determine an expression for the total electric field at a point A (r0 = 3.6L,0) in terms of q and L. Calculate the magnitude of the total electric field at A, when q = 7.60 x 10-07 C and L = 50.0 cm.
Explanation / Answer
electric field at x units on central axis due to dipole is EF = 2P/4 pi eo r^3
where P = 2a q here P= 2* 0.5 * 7.6uC = 7.6 u N/C
thus EF = 2* 7.6*10^-6/ (4*3.14*8.85*10^-12 * ( 3.6*0.5)^3
Ef =1.40*10^5 N/C
A) The direction of the net electric field at the origin is W---------------true
B) The direction of the net electric field at a point on the negative y-axis is SE-------false
C) The magnitude of the net electric field at point A is greater than the magnitude
of the net electric field at the origin.--- false
D) The direction of the net electric field at the point (-r0,0) is W-------------true
E) The direction of the net electric field at a point on the positive y-axis is W----flase
F) The direction of the net electric field at A is W----------true
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