A shot putter releases the shot some distance above the level ground with a velo

Question

A shot putter releases the shot some distance above the level ground with a velocity of 11.0 m/s, 49.6

A shot putter releases the shot some distance above the level ground with a velocity of 11.0 m/s, 49.6 degree above the horizontal. The shot hits the ground 2.06 s later. You can ignore air resistance. (Assume the horizontal direction of the shot and upward are positive.) What are the components of the shot's acceleration while in flight? What are the components of the shot's velocity at the beginning of its trajectory? What are the components of the shot's velocity at the end of its trajectory? How far did she throw the shot horizontally? Why does the expression for R (as given below) not give the correct answer for part (c)? It is not a projectile motion. The initial and final heights are different. There is air drag. How high was the shot above the ground when she released it?

Explanation / Answer

a) -g j = -9.8m/s^2

horizontal component = 0

vertical component = -9.8 m/s^2

b) V = (11 m/s)cos(49.6)i + (11 m/s)sin(49.6)j = 7.129i + 8.377j

horizontal componenet = 7.129

vertical componeent = 8.377

at the end of trajectory

Vx =7.129 i (doesn

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