At what two times is the baseball at a height of 10.0 above the point at which i

Question

At what two times is the baseball at a height of 10.0 above the point at which it left the bat?

Calculate the horizontal component of the baseball's velocity at each of the two times you found in part A.

Calculate the vertical component of the baseball's velocity at each of the two times you found in part A.

A major leaguer hits a baseball so that it leaves the bat at a speed of 28.0 m/s and at an angle of 35.7 ? above the horizontal. You can ignore air resistance. At what two times is the baseball at a height of 10.0 above the point at which it left the bat? Calculate the horizontal component of the baseball's velocity at each of the two times you found in part A. Calculate the vertical component of the baseball's velocity at each of the two times you found in part A.

Explanation / Answer

a) y = y0 + v0y t + 1/2 a t^2

10 = 28*sin(35.7)*t - 0.5*9.81*t^2

t=0.808s and 2.523 s

b) horizontal doesnt change, 28*cos(35.7)=22.738 m/s

c) 28*sin(35.7)-9.81*0.808=8.41 m/s

when going down -8.41 m/s

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