The capacitive network shown in the figure is assembled with initially uncharged
ID: 2132896 • Letter: T
Question
The capacitive network shown in the figure is assembled with initially uncharged capacitors. A potential difference, Vab=+100V, is applied across the network.
a) What is equivalent capacitance Ceq of the network if the switch S in the network is kept open?
b) Whati is the total energy stored in the seven capacitors when the swithc S is closed?
c) What are the voltages across each capacitor when the switch S is kept open when the external source is connected?
Explanation / Answer
Find the equivalent capacitance of the circuit, which is equal to be 14.4x10^-6F.
Using Q=CV, find the charge in the circuit, which is 14.4x10^-4C
Divide this charge in the ratio of 9.6: 4.8 so that 4.8x10^-4 C of charge in the branch of the circuit.
Divide this charge in the ratio of 9:15 so that 3x10^-4 C of charge flows in 15micro F capacitor.
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