A positive charge q 1 is located 5.00 m to the left of a negative charge q 2 . T

Question

A positive charge q1 is located 5.00 m to the left of a negative charge q2. The charges have different magnitudes. On the line through the charges, the net electric field is zero at a spot 1.00 m to the right of the negative charge. On this line there are also two spots where the total electric potential is zero. Locate these two spots relative to the negative charge.

x =
m to the right of the negative charge x = m to the left of the negative charge

I am very stuck on this problem and would love for someone to show me the steps and how to get the answer, thank you.

Explanation / Answer

Considering the forces

q1/ (5 +1) ^2 = q2/ 1^2

q1/q2 = [6/ 1] ^2 = 36

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Considering the potentials

q1 /d1 = q2 /d2

d1/ d2= q1/q2 =36

d1 = 36 d2

case1:

d1 +d2 = 5m

d2 = 5/ 37 = 0.135 m from the negative charge toward the positive charge

case2:

d1

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