(A) Flux and conducting shells. A charged particle is held at the center of two
ID: 2132511 • Letter: #
Question
(A) Flux and conducting shells. A charged particle is held at the center of two concentric conducting spherical shells. The figure on the left shows a cross section. The figure on the right gives the net flux ? through a Gaussian sphere centered on the particle, as a function of the radius r of the sphere. The scale of the vertical axis is set by ?s = 2.0
Flux and conducting shells. A charged particle is held at the center of two concentric conducting spherical shells. The figure on the left shows a cross section. The figure on the right gives the net flux ? through a Gaussian sphere centered on the particle, as a function of the radius r of the sphere. The scale of the vertical axis is set by ?s = 2.0 times106 N*m2/C. What is the charge of the central particle? What is the net charge on shell A? What is the net charge on shell B?Explanation / Answer
For a flux equal to magnitude "phi"s, from gauss law, we get charge magnitude equal to 17.7*10^(-6) C.
Now charge at flux = (-1.8)"phi"s will be the charge at centre equal to -2(1.8)17.6 = -63.72 *10^(-6) C.
Now the flux = .8"phi"s will be generated from charge at centre plus charge on shell A.
Charge from .8 "phi"s flux = .8*17.72 = 141.46*10^(-6) C
= charge from shell A plus charge from centre= X(say) .
At flux = -.4"phi"s, net charge = 17.7*-.4 = -70.8*10^(-6) C= Y(say).
Now Y is equal to charge on A +B+ centre.
So charge on shell B = Y-X = -70.66*10^(-6) C.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.