a) Find the direction and magnitude of F tot , the total force exerted on her by

Question

a) Find the direction and magnitude of Ftot, the total force exerted on her by the others, given that the magnitudes F1 and F2 are 26.8 N and 18.2 N, respectively.

Find the direction and magnitude of Ftot, the total force exerted on her by the others, given that the magnitudes F1 and F2 are 26.8 N and 18.2 N, respectively. (counterclockwise from the direction of F1 is positive) What is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of Ftot? What is her acceleration assuming she is already moving in the direction of Ftot? Remember that friction is always in the opposite direction of motion or attempted motion between surfaces in contact.

Explanation / Answer

Net force = sqrt(26.8^2 + 18.2^2) = 32.39 N

Direction = tan^-1 (18.2/26.8) = 34.18 degrees

Initial acceleration= 32.39/65 = 0.498 m/s^2

accleration asuming constant speed in that direction will be zero

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