THE CHI-SQUARE VALUE FROM QUESTION 23 IS 643 50 45 2 1.39 3 2.37 05 3.84 5.99 7.

Question

THE CHI-SQUARE VALUE FROM QUESTION 23 IS 643

50 45 2 1.39 3 2.37 05 3.84 5.99 7.81 001 6.63 9.21 11.34 Degrees of freedom 24. Based on the table above (which is similar to the one in your lab manual, in the appendix), which of the following could reasonably be concluded from your Chi- square value from question 23? A) Independent assortment is supported, the loci are linked assortment is rejected because the Chi-square value is smaller than the critical value C) Independent assortment is supported because the Chi-square value is small D) The Chi-square value is larger than the critical value, thus, independent assortment is falsified E) The Chi-square value is too large to show anything

Explanation / Answer

Answer:

Based on the given information, The Chi square value is 643.

The probability value corresponding to a Chi Square value of 643 with 2 degree of freedom is P-Value is < 0.00001. The result is significant at p < 0.05.

Since the Chi square value is greater than the critical value and P-value is smaller as compared to significance level, therefore Null Hypothesis is rejected and Alternative hypothesis is accepted.

So the correct conclusion is: D) The Chi Square value is larger than the critical value, thus, independent assortment is falsified.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.