As illustrated in the figure below, a negatively charged particle is released fr

Question

As illustrated in the figure below, a negatively charged particle is released from rest at point B and accelerates until it reaches point A. The mass and charge of the particle are 9.00 times 10-6 kg and -4.00 times 10-5 C, respectively. Only the gravitational force and the electrostatic force act on the particle, which moves on a horizontal straight line without rotating. The electric potential at A is 34 V greater than that at B; in other words, VA ? VB = 34 V. What is the translational speed of the particle at point A?

Explanation / Answer

qV = mv^2/2

4 x 10-5 x 34 = 9 x 10-6 x v^2/2

v = 17.38 m/s

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