As shown, a server at a restaurant is carrying a tray that has a glass of water
ID: 2128849 • Letter: A
Question
As shown, a server at a restaurant is carrying a tray that has a glass of water resting on it. (Figure 3) The glass and tray exert a force with magnitude F1 = 25.0N on the server's hand. If l1 = 0.441m , l2 = 0.304m , l3 = 0.136m , ?1 = 165?, and ?2 = 130?, what is the moment of force about the shoulder joint at point A? Assume that moments acting in the counterclockwise direction about point A are positive whereas moments acting in the clockwise direction are negative. Express your answer numerically in newton-meters to three significant figures. http://session.masteringengineering.com/problemAsset/1174171/8/1108610_003.jpgPlease do not convert the values to ft or pound. keep the question as it is. thanks As shown, a server at a restaurant is carrying a tray that has a glass of water resting on it. (Figure 3) The glass and tray exert a force with magnitude F1 = 25.0N on the server's hand. If l1 = 0.441m , l2 = 0.304m , l3 = 0.136m , ?1 = 165?, and ?2 = 130?, what is the moment of force about the shoulder joint at point A? Assume that moments acting in the counterclockwise direction about point A are positive whereas moments acting in the clockwise direction are negative. Express your answer numerically in newton-meters to three significant figures. http://session.masteringengineering.com/problemAsset/1174171/8/1108610_003.jpg
Please do not convert the values to ft or pound. keep the question as it is. thanks As shown, a server at a restaurant is carrying a tray that has a glass of water resting on it. (Figure 3) The glass and tray exert a force with magnitude F1 = 25.0N on the server's hand. If l1 = 0.441m , l2 = 0.304m , l3 = 0.136m , ?1 = 165?, and ?2 = 130?, what is the moment of force about the shoulder joint at point A? Assume that moments acting in the counterclockwise direction about point A are positive whereas moments acting in the clockwise direction are negative. Express your answer numerically in newton-meters to three significant figures. Please do not convert the values to ft or pound. keep the question as it is. thanks
Explanation / Answer
The vector components of the different distances are
(1,35*cos155/1,35sin155)
(0,95cos50/0,95sin50)
(0,5cos0/0,5sin0)
the force position is (- 0,112867/1,29)
the sum of the x components is the perpendicular distance of the force from A = 0.112867
The force is 7,1 lb, the moment is 7,1*0,112867 = 0,801 lb*ft
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