ball a rolls at a constant speed of 0.25m/s on a table 0.70m above the floor, an

Question

ball a rolls at a constant speed of 0.25m/s on a table 0.70m above the floor, and ball B rolls on the floor directly under the first ball with the same speed and direction. When ball A hits the floor, how far from the point directly below the edge of the table will each ball be ball a rolls at a constant speed of 0.25m/s on a table 0.70m above the floor, and ball B rolls on the floor directly under the first ball with the same speed and direction. When ball A hits the floor, how far from the point directly below the edge of the table will each ball be

Explanation / Answer

time taken by ball A to reach the floor = t = sqrt (2h/g)

=> t = sqrt (2*0.7/9.8) = 0.378 s

so distance travelled = 0.378 * 0.25 = 0.0945 m

since both balls have same initial velocities and ideal situation is considered so both balls will meet at 0.0945 m from edge of table.

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