1. A 33-? resistor has a voltage difference of 8 V across its leads. (a) What is
ID: 2128171 • Letter: 1
Question
1. A 33-? resistor has a voltage difference of 8 V across its leads.
(a) What is the current through the resistor?
________ A
(b) What is the power being dissipated in this resistor?
_________ W
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2. A toaster draws a current of 7 A when it is connected to a 220-V ac line.
(a) What is the power consumption of this toaster?
________ W
(b) What is the resistance of the heating element in the toaster?
_____________ ?
________________________________________________________________
A 33-? resistor has a voltage difference of 8 V across its leads. What is the current through the resistor? ________ A What is the power being dissipated in this resistor? _________ W A toaster draws a current of 7 A when it is connected to a 220-V ac line. What is the power consumption of this toaster? ________ WWhat is the resistance of the heating element in the toaster? _____________ ? In the circuit shown below, the r = 2-? resistance is the internal resistance of the battery and can be considered to be in series, as shown, with the battery and the R = 7-? load. (Let epsilon = 5 V What is the current flowing through the 7-? resistor? ______________ A What is the voltage difference across the 7-? resistor? ______________ V Three resistors are connected to a 8-V battery as shown. The internal resistance of the battery is negligible. What is the current through the 15-? resistance? ______________A Does this same current flow through the 25-? resistance? Yes No What is the voltage difference across the 20-? resistance? _______________V Three identical resistances, each 10 ?, are connected in parallel with one another as shown below. The combination is connected to a 18-V battery whose internal resistance is negligible. What is the equivalent resistance of this parallel combination? ____________ ?What is the total current through the combination? ____________ A How much current flows through each resistor in the combination? ___________ AExplanation / Answer
1).
V = I*R (V=voltage, I = current, R = resistance)
power = (V*V)/R = I*V
a) current,I = V/R = 8/33 = 0.24
b) power = 8*8/33 = 1.94
2). power = (V*V)/R = I*V
a) => power = 7*220 = 1540 W (this is avg power in case of AC)
b) => R = V/I = 220/7 = 31.42 ohm
3). total resistance = R + r = 7+2 = 9 ohm
total current = V/R = 5/9 = 0.56 A
and current in series is same
a). => current flowing through the 7 ohm resistor = 0.56A
b). Voltage diff in 7 ohm register = I*R = 0.56*7 = 3.89 V
4). connected in series so current will be same
total Resistance = 15 + 20+ 25 = 60
current in circuit = 8/60 = 0.133 I
a). the current through the 15 ohm resistance = 0.133 I
b). Yes.. since its a series connection
c) voltage difference across the 20 ohm resistance = I*R = 0.133 * 20
= 2.66 V
5) this is parallel connection..
here voltage difference will be same but current will be different
since all the resistance are of 10 ohm current will divide equally
totol resistance, R in parallel can be calculated as..
1/R = 1/(R1) + 1/(R2) 1/(R3) +... and so on..
where R1,R2,R3.. are resistances connected in parallel
so total resistance of this circuit =>
1/R = 1/10 + 1/10 + 1/10
=> 1/R = 3/10
=> R = 10/3 = 3.33
a). equvivalent resistance = 3.33 ohm
b). total current = V/R = 18/3.33 = 5.4 A
c). current in each resistor = (total current)/3
=> 5.4/3 = 1.8 A
NOTE : total current is not same in parallel when registers are not same
you will have to calculate it using I=V/R (V remains same in parallel connection)
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