1. An average force of 200 N acts for a time interval of 0.06 s on a golf ball.

Question

1. An average force of 200 N acts for a time interval of 0.06 s on a golf ball.

(a) What is the magnitude of the impulse acting on the golf ball?

_______ N

What is the magnitude of the impulse acting on the golf ball? _______ N middot s What is the change in the golf ball's momentum? _______ kg middot m/s A ball traveling with an initial momentum of 1.5 kg middot m/s bounces off a wall and comes back in the opposite direction with a momentum of ?1.5 kg middot m/s. What is the change in momentum of the ball? _________ kg middot m/s What impulse would be required to produce this change?_________ N middot s

Explanation / Answer

IMPULSE=f*t=200*0.06=12

b)12 impulse = change in the golf ball's momentum

c) 3

d) 3

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