Starting from home, you bicycle 26 km north in 2.5 h and then turn around and pe

Question

Starting from home, you bicycle 26kmnorth in 2.5h and then turn around and pedal straight home in 1.5h . What are your (a) displacement at the end of the first 2.5h, (b) average velocity over the first 2.5h , (c) average velocity for the homeward leg of the trip, (d) displacement for the entire trip, and (e) average velocity for the entire trip?

Starting from home, you bicycle 26km { m km}north in 2.5h { m h}and then turn around and pedal straight home in 1.5h { m h}. What are your (a) displacement at the end of the first 2.5h{ m h}, (b) average velocity over the first 2.5 h { m h}, (c) average velocity for the homeward leg of the trip, (d) displacement for the entire trip, and (e) average velocity for the entire trip?

Explanation / Answer

a) 26 km

b) 26/2.5 = 10.4 km/hr

c) 26/1.5 = 17.33 km/hr

d) net displacement = 0

e) v = displacement/time = 0

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