In the Bohr model of the hydrogen atom, the electron orbits the proton in unifor

Question

In the Bohr model of the hydrogen atom, the electron orbits the proton in uniformly circular motion.        The radius of the circle is quantized to certain values given by         

• r = n

2a0,             for n = 1, 2, 3, . . .        where a0 = 52.92 pm. (5+4+7+4=20 points)                  

1. What is the speed of the electron if it orbits in the smallest allowed orbit (n = 1)?                    
2. What is the speed of the electron if it orbits in the second smallest orbit?                    
3. How much work is need to be done to move the electron from the smallest orbit to the next? kjl                   
4. Explain the sign of the work you calculated in c).

Explanation / Answer

1)2.19*10^6 m/sec...

2)2.19*10^6/2=1.095*10^6 m/sec....

3)3.4-13.6=-10.2 eV......

4) negative sign

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.