1- A tuning peg slips on your violin, lessening the tension in one of the string

Question

1-A tuning peg slips on your violin, lessening the tension in one of the strings. What effect does this change have on the string's sound?

a-It lowers the pitch (vibrational frequency) of the string.

b-It raises the pitch (vibrational frequency) of the string.

c-It increases the volume of the string, but has no effect on the string's pitch.

d-It decreases the volume of the string, but has no effect on the string's pitch.

2-Some of the strings in a piano are made of steel wire wrapped with a spiral of copper wire. The copper wire doesn't contribute to the tension in the string, so what is its purpose?

a-It increases the mass of the string, thereby lowering the string's pitch.

b-It increases the mass of the string, thereby raising the string's pitch.

c-It decreases the mass of the string, thereby raising the string's pitch

d-It decreases the mass of the string, thereby lowering the string's pitch.

3-Some wind chimes consist of sets of metal rods that emit tones when they're struck by wind-driven clappers. These equal-diameter rods bend back and forth as harmonic oscillators. Why do the longer rods emit lower pitched tones than the shorter rods?

a-The longer rods have less mass and are less stiff than the shorter rods.

b-The longer rods have more mass and are less stiff than the shorter rods.

c-The longer rods have less mass and are stiffer than the shorter rods.

d-The longer rods have more mass and are stiffer than the shorter rods.

4-What is the interval between an octave?

a-3/2

b-5/1

c-2/1

d-1/3

5-The natural resonance of a harmonic oscillator is the vibrational mode that the system is optimized for.  Or in other words, it is the particular motion of a spring-like system that is repeated over and over again.  What is the first mode of operation of any harmonic oscillator?

a-higher-order mode

b-fundamental mode

c-initial mode

d-basic mode

Explanation / Answer

1

a-It lowers the pitch (vibrational frequency) of the string.

velocity = frequesny x lamda = root (T/ u)

lamda = walength = does not change as the length does not chage

u = mass per unit length

T = tension

2

a-It increases the mass of the string, thereby lowering the string's pitch.

same formula as above

3

b-The longer rods have more mass and are less stiff than the shorter rods.

mass = linear mass density x length

4

c-2/1

any two notes an octave apart have a frequency ratio of 2:1.

5

b-fundamental mode

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.