<?xml:namespace prefix = span style=\"font-size /> an aluminum shpere initially

Question

<?xml:namespace prefix = spanfont-size:small;">an aluminum shpere initially at tempreture of 100 c and dimeter 2.54508 cm is placed on top of a copper ring initially at temprture of 0.0 c and dimeter of 2.54000 cm .the two are allowed to come to equlibrium , no heat  lost to surrounding. given the mass of ring to be  0.03 kg detrmin the mass of the shpere.style="font-size: small;" data-mce-style="font-size: small;">

specific heat of copper 386 J/Kg.Kstyle="font-size: small;" data-mce-style="font-size: small;">

===========  ALuminum 900J/Kg .Kstyle="font-size: small;" data-mce-style="font-size: small;">

thermal expantion of copper  17*10^-6 /Kstyle="font-size: small;" data-mce-style="font-size: small;">

===============of aluminum 23*10^-6/Kstyle="font-size: small;" data-mce-style="font-size: small;">

Explanation / Answer

m1 c1 deltaT1 = m2 c2 deltaT2

m * 900 * (100-T) = 0.03*386*(T - 0)

WE need T, equilibrium temperature to find m.

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.