Question
Hello, I'm having really hard time with these physics questions
A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by x = 19.0t and y = 4.08t - 5.132t , where x and y are in meters and t is in seconds. Write a vector expression for the ball's position as a function of time, using the unit vectors i and j. (Give the answer in terms of t.) = By taking derivatives, do the following. (Give the answers in terms of t.) obtain the expression for the velocity vector v as a function of time = obtain the expression for the acceleration vector a as a function of time = Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t = 2.97 s. =m = m/s = m/s2 A particle initially located at the origin has an acceleration of = 2.00 m/s2 and an initial velocity of i = 6.00 m/s. Find the vector position of the particle at any time t (where t is measured in seconds). (t +t2 ) m Find the velocity of the particle at any time t. ( +t ) m/s Find the coordinates of the particle at t = 1.00 s. x = m y =m Find the speed of the particle at t = 1.00 s. m/s The vector position of a particle varies in time according to the expression r = 8.40 i - 8.60t2 j where r is in meters and t is in seconds. Find an expression for the velocity of the particle as a function of time. (Use any variable or symbol stated above as necessary.) = m/s Determine the acceleration of the particle as a function of time. (Use any variable or symbol stated above as necessary.) = m/s2 Calculate the particle's position and velocity at t = 5.00 s. = m/s = m/s A fish swimming in a horizontal plane has velocity = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to a certain rock is r1 = (14.0 - 4.20 ) m. Afte fish swims with constant acceleration for 17.0 s, its velocity is = (25.0 - 6.00 ) m/s. What are the components of the acceleration of the fish? ax = m/s2 ay =m/s2 What is the direction of its acceleration with respect to unit vector ? degree counterclockwise from the +x-axis If the fish maintains constant acceleration, where is it at t = 28.0 s? x = m y = m In what direction is it moving? degree counterclockwise from the +x-axis Consider the two vectors = - 3 and = - - 4 . Calculate + + Calculate - + Calculate | + | Calculate | - | Calculate the directions of + and - . A + B degree (counterclockwise from the +x axis) - degree (counterclockwise from the +x axis) A blue car of length 4.49 m is moving north on a roadway that intersects another perpendicular roadway (see figure below). The width d of the intersection from near edge to far edge is 26.5 m. The blue car has a constant acceleration of magnitude 1.60 m/s2 directed south. The time interval required for the nose of the blue car to move from the near (south) edge of the intersection to the north edge of the intersection is 3.60 s How far is the nose of the blue car from the south edge of the intersection when it stops? For what time interval is any part of the blue car within the boundaries of the intersection? A red car is at rest on the perpendicular intersecting roadway. As the nose of the blue car enters the intersection, the red car starts from rest and accelerates east at 5.80 m/s2. What is the minimum distance from the near (west) edge of the intersection at which the nose of the red car can begin its motion if it is to enter the intersection after the blue car has entirely left the intersection? m If the red car begins its motion at the position given by the answer to part (c), with what speed does it enter the intersection? m/s
Explanation / Answer
hi there, all our experts will be busy in answering and think no will be nterteded in answering such a long question, tough points are more, advice is that please try make only one question per for 300 points, so that u will get response. its cost u them same points but iam sure you wll results with this. sry for not making this time. HAPPY LEARNNG
1. r = 19i + (4.08 t-5.13t^2)j
v = dr/dt = 0 + 4.08 j -10.26 j t m/s
accleration a = dv/dt = -10.26j m/s^2
