A A ball is thrown from the ground into the air. At a height of 9.1 m, the veloc

Question

A A ball is thrown from the ground into the air. At a height of 9.1 m, the velocity is observed to be v = 7.1i + 6.8j in meters per second (x axis horizontal, y axis vertical and up).

(a) To what maximum height will the ball rise?
m

(b) What will be the total horizontal distance traveled by the ball?
m

(c) What is the magnitude of the ball's velocity the instant before it hits the gound?
m/s
What is the direction of the ball's velocity the instant before it hits the ground?

A A ball is thrown from the ground into the air. At a height of 9.1 m, the velocity is observed to be v = 7.1i + 6.8j in meters per second (x axis horizontal, y axis vertical and up).

(a) To what maximum height will the ball rise?
m

(b) What will be the total horizontal distance traveled by the ball?
m

(c) What is the magnitude of the ball's velocity the instant before it hits the gound?
m/s
What is the direction of the ball's velocity the instant before it hits the ground?

A A ball is thrown from the ground into the air. At a height of 9.1 m, the velocity is observed to be v = 7.1i + 6.8j in meters per second (x axis horizontal, y axis vertical and up).

(a) To what maximum height will the ball rise?
m

(b) What will be the total horizontal distance traveled by the ball?
m

(c) What is the magnitude of the ball's velocity the instant before it hits the gound?
m/s
What is the direction of the ball's velocity the instant before it hits the ground?

Explanation / Answer

a)

9.8*9.1+0.5*6.8^2 = 9.8*h

So, h = 11.46 m <-------------answer

b)

total horizontal distance = 7.1*sqrt(9.8*11.46*2)*2/9.8 = 21.72 m

c)

magnitude = sqrt(2*9.8*11.46+6.8^2) = 16.46 m/s

d)

direction = 180 - atan(6.8/sqrt(2*9.8*11.46)) = 155.6 degrees with the +ve x axis counterclockwise direction

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