Water flows steadily from an open tank as shown in the figure. ( Figure 1 ) The
ID: 2125746 • Letter: W
Question
Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of point 1 is 10.0 meters, and the elevation of points 2 and 3 is 2.00 meters. The cross-sectional area at point 2 is 0.0480 square meters; at point 3, where the water is discharged, it is 0.0160 square meters. The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe.
Assuming that Bernoulli's equation applies, compute the discharge rate dVdt.
Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of point 1 is 10.0 meters, and the elevation of points 2 and 3 is 2.00 meters. The cross-sectional area at point 2 is 0.0480 square meters; at point 3, where the water is discharged, it is 0.0160 square meters. The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. Assuming that Bernoulli's equation applies, compute the discharge rate dVdt.Explanation / Answer
v = sqrt(2*g*h) = sqrt(2*9.8*8) = 12.52 m/s
volume flow rate = dV/dt = A*v = 0.2 m^3/s
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.