Three spiders are resting on the vertices of a triangular web. The sides of the

Question

Three spiders are resting on the vertices of a triangular web. The sides of the triangular web have a length of a = 0.68 m, as depicted in the figure. Two of the spiders (S1 and S3) have +8.9

Three spiders are resting on the vertices of a triangular web. The sides of the triangular web have a length of a = 0.68 m, as depicted in the figure. Two of the spiders (S1 and S3) have +8.9 mu C charge, while the other (S2) has ?8.9 mu C charge. What are the magnitude and direction of the net force on the third spider (S3)? What are the magnitude and direction of the net force on the third spider (S3) when it is resting at the origin?

Explanation / Answer

a)

Magnitude = (2*9*10^9*(8.9*10^-6)^2/0.68^2)*cos(60 degree) = 1.54 N

Direction : Downwards.....(270 from x-axis in Counterclockwise )

c)

Magnitude = (2*9*10^9*(8.9*10^-6)^2/(0.68/2)^2 = 12.334 N

Direction : Downwards.....(270 from x-axis in Counterclockwise )

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