a) Find E y such that the particle will cross the x axis at x = 1.5 cm if the pa
ID: 2124701 • Letter: A
Question
a) Find Ey such that the particle will cross the x axis at x = 1.5 cm if the particle is an electron.
_______N/C
b) Find Ey such that the particle will cross the x axis at x = 1.5 cm if the particle is a proton.
_______N/C
A particle leaves the origin with a speed of 3.3 times 106 m/s at 36 degrees to the positive x axis. It moves in a uniform electric field directed along positive y axis. Find Ey such that the particle will cross the x axis at x = 1.5 cm if the particle is an electron. Find Ey such that the particle will cross the x axis at x = 1.5 cm if the particle is a proton.Explanation / Answer
Part A)
The y component of the velocity = 3.3 X 10^6 (sin 36) = 1.94 X 10^6 m/s
The x component is (3.3 X 10^6)(cos 36) = 2.69 X 10^6 m/s
Start with d = vt in the x
.015 = (2.69 X 10^6)(t)
t = 5.57 X 10^-9 sec
In the y,
vf = vo + at
-1.94 X 10^6 = 1.94 X 10^6 + (a)(5.57X 10^-9)
a = 6.97 X 10^14 m/s^2
F = ma
F = (9.11 X 10^-31)(6.97 X 10^14)
F = 6.35 X 10^-16 N
F = qE
(6.35X 10^-16) = (1.6 X 10^-19)(E)
E = 3967 N/C
Part B)
SAME IDEA, NOW A PROTON
The y component of the velocity = 3.3 X 10^6 (sin 36) = 1.94 X 10^6 m/s
The x component is (3.3 X 10^6)(cos 36) = 2.69 X 10^6 m/s
Start with d = vt in the x
.015 = (2.69 X 10^6)(t)
t = 5.57 X 10^-9 sec
In the y,
vf = vo + at
-1.94 X 10^6 = 1.94 X 10^6 + (a)(5.57X 10^-9)
a = 6.97 X 10^14 m/s^2
F = ma
F = (1.67 X 10^-27)(6.97 X 10^14)
F = 1.16 X 10^-12 N
F = qE
(1.16 X 10^-12) = (1.6 X 10^-19)(E)
E = 7.27 X 10^6 N/C
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.