For full points I would like to see the work and a correct answer. Thank you. An

ID: 2124060 • Letter: F

Question

For full points I would like to see the work and a correct answer.

Thank you.

An arterial constriction causes the radius of an artery to decrease from its normal value of 4mm to 2.5 mm.

The average speed of the blood in the artery is Vo in the unrestricted segment, and V in the restricted segment.

The flow rate through this artery is .753 liters/min.

1. Calculate the volume flow rate through the artery in M^3/s. Calculate Vo.

2. Calculate V, the average blood flow speed in constricted portion.

3. Use Bernoulli's equation to calculate the difference in pressure between the two ends of the segment of artery

represented above.

Q = A*Vo

A = pi*d^2/4 = 1.256*10^-5

Q = 0.753 lit/min = 0.753*10^-3 /60 m^3/s = 1.255*10^-5

V0 = 0.999 m/s

A0*V0 = A1*V

V = (4/2.5)^2 *0.999 =2.557 m/s

desity of blood =1060

P1+1/2*p*Vo^2 = P2 +1/2*p*V^2

P1-P2 = 1/2*p*(V^2-Vo^2)

P1-P2 = 1/2*1060*(2.557 ^2 - 0.999^2) = 2937.5 Pa

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.