The polarizers are rotated, so that the second polarizer has a transmission of 4

Question

The polarizers are rotated, so that the second polarizer has a transmission of 43.6 degrees with respect to the first polarizer and the third polarizer has an angle of 90 degrees with respect to the first. If "Ib" is the intensity of the original unpolarized light, find the intensity of the beam at the following times.

After passing through the second polarizer________

after passing through the third polarizer__________

and What is the final intensity if the second polarizer is removed? ______________

Explanation / Answer

lose half rst polarizer

so after second

I = 1/2 * cos(43.6)^2=0.262

after third

I = 0.262*cos(46.4)^2=0.147

if you remove the 2nd, there is a 90 degree angle so I = 0

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