A 1.5 cm object is placed at a distance of 5.0 cm from the centerline of a thin
ID: 2123671 • Letter: A
Question
A 1.5 cm object is placed at a distance of 5.0 cm from the centerline of a thin diverging lens with a focal length of 8.0 cm.
a. draw a ray diagram indicating the positions of the object, the image, the focal points of the lens and the relative heights of the object and the image.
b. calculate the height of the image
A blue-green light with %u03BB = 490 nm passes through two 2.50 %u03BCm width slits separated by a distance of 0.050 mm. Calculate the following:
a. the angle of second intensity maximum to one side of the central intensity maximum. b. the angle of the first %u201Cmissing%u201D intensity maximum to one side of the central maximum.
Explanation / Answer
v= uf/u-v = 5*8/-13 = 3.076 cm
m = V/u = 3.076/5 = 0.615
h' = 0.615 *1.5 =0.92 cm
b.
d sin A = mL
for second maximum, m=2
sinA = 2* 490nm/2.5um
sinA =0.392
A = 23.07 deg
b. for m=1,
sinA = 490nm/2.5um =0.196
A =11.303 deg
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