You are on a train that is traveling at 3.0 m/s along a level straight track. Ve

Question

You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that slopes upward at a 12? angle with the horizontal. As you face the window (0.923 m high, 1.92 m wide) in your compartment, the train is moving to the left, as the drawing indicates. The top edge of the wall first appears at window corner A and eventually disappears at window corner B. How much time passes between appearance and disappearance of the upper edge of the wall?

Explanation / Answer

time = distance/velocity. You can see that at a time 1.92/3 = 0.64 seconds after the edge appears at A, that point on the wall will be at the bottom corner below corner B. What further D distance does the train have to travel so that the wall is 1m higher? 1/D = tan(12) D= 1/tan(12) = 4.705 m At 3 m/s that will take 4.705/3 = 1.568 s The total time from appearing at A to disappearing at B is therefore 0.64 + 1.568 = 2.208 s=2.21sec(approx)

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