You wish to design a telescope using an objective lens with f(objecive) = 0.75 m

Question

You wish to design a telescope using an objective lens with f(objecive) = 0.75 m. If you use an eyepiece with a magnification of 20, what is the total magnification of the telescope and what is the length of the telescope?

Need to be explained, not just answered :) Will rate life saver :)
You wish to design a telescope using an objective lens with f(objecive) = 0.75 m. If you use an eyepiece with a magnification of 20, what is the total magnification of the telescope and what is the length of the telescope?

Need to be explained, not just answered :) Will rate life saver :)

Explanation / Answer

given that f0 = 0.75m magnification = m = 20

M=si/feyepiec


si to be 25cm as near point standard.


20=0.25/feyepiece

f eye= 0.0125


length of telescope = L = f0 + fe   =
0.0125+0.75 =0.7625 m plug in values L =0.7625 m


M = N / f

=0.75/0.0125= 60 given that f0 = 0.75m magnification = m = 20

M=si/feyepiec


si to be 25cm as near point standard.


20=0.25/feyepiece

f eye= 0.0125


length of telescope = L = f0 + fe   =
0.0125+0.75 =0.7625 m plug in values L =0.7625 m


M = N / f

=0.75/0.0125= 60 given that f0 = 0.75m magnification = m = 20

M=si/feyepiec


si to be 25cm as near point standard.


20=0.25/feyepiece

f eye= 0.0125


length of telescope = L = f0 + fe   =
0.0125+0.75 =0.7625 m plug in values L =0.7625 m


M = N / f

=0.75/0.0125= 60 plug in values L =0.7625 m


M = N / f

=0.75/0.0125= 60

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