Two blocks are connected with the massless, non-stretchable rope, and connected
ID: 2122405 • Letter: T
Question
Two blocks are connected with the massless, non-stretchable rope, and connected to the spring that is fixed to the wall as shown. One of the blocks is hanging from the side of the table, while the other lies on the table. Mass of each block m = 0.5 kg, spring stiffness k=40 N/m, friction coefficient between the block and the table mu = 0.2. The spring is originally unstretched while the blocks are held at rest. Find maximum velocity (v max) of the blocks once the system is released (i.e. the hanging block starts to go down).
Explanation / Answer
now coside m which is on the table
T-mu*m*g-kx=m*a
T=mg
mg*(1-mu)-kx=m*dv/dt
(g*(1-mu)-kx)dx=vdv
integrate it we get
v(x)=2*sqrt(g(1-mu)x-kx^2/2)
For V max. Dv/dx=0
1-mu-(kx)=0
x=1-mu/k
x=0.02 m
Max V=2*sqrt(g(1-mu)x-kx^2/2)
=0.77 m/s ans
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