A merry-go-round starts from rest and reaches the angular speed of 4 rpm in the

Question

A merry-go-round starts from rest and reaches the angular speed of 4 rpm in the first two minutes. What would be the angular acceleration of the merry-go-round in rpm/min?
A spring is hanging from a ceiling with 50g mass attached. When the mass is pulled down from the equilibrium and released, it oscillates with 0.4s period. The spring constant is equal to? Question 16 options:
A merry-go-round starts from rest and reaches the angular speed of 4 rpm in the first two minutes. What would be the angular acceleration of the merry-go-round in rpm/min? A merry-go-round starts from rest and reaches the angular speed of 4 rpm in the first two minutes. What would be the angular acceleration of the merry-go-round in rpm/min?

A spring is hanging from a ceiling with 50g mass attached. When the mass is pulled down from the equilibrium and released, it oscillates with 0.4s period. The spring constant is equal to? A spring is hanging from a ceiling with 50g mass attached. When the mass is pulled down from the equilibrium and released, it oscillates with 0.4s period. The spring constant is equal to?

Explanation / Answer

ang.accelaration alpha =(Wf-Wi)/t.....=4/2=2 rpm/min^2......

B) spring constant k=( 4*pi^2*m)/T^2=12.34 N/m

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