Rank in order, from most positive to most negative, the image heights in the fol
ID: 2122070 • Letter: R
Question
Rank in order, from most positive to most negative, the image heights in the following situations:
Rank from most positive to most negative. To rank items as equivalent, overlap them
1. A 1.0-cm-tall object is 8 cm from a converging lens of focal length of 10 cm.
2. A 1.5-cm-tall object is 7 cm from a diverging lens of focal length of -10 cm.
3. A 2.0-cm-tall object is 15 cm from a converging lens of focal length of 13 cm.
4. A 2.5-cm-tall object is 16 cm from a diverging lens of focal length -13 cm.
If you could show your work, I would appreciate it ... I know there is a question similar to this.. but that answer is wrong.. thank you so much
If the answer is correct, I will rate you LIFESAVER!!!
AND ARE THERE DIFFERENT EQUATIONS FOR CONVERGING AND DIVERGING LENSES???
Explanation / Answer
1. A 1.0-cm-tall object is 8 cm from a converging lens of focal length of 10 cm.
1/q = 1/f - 1/p = 1/10 - 1/8
q = -40 cm
h' = h * (-(-40/8)) = 1 * 5 = 5 cm
2. A 1.5-cm-tall object is 7 cm from a diverging lens of focal length of -10 cm.
1/q = 1/f - 1/p = 1/(-10) - 1/7
q = -4.12 cm
h' = 1.5 * (-(-4.12/7)) = 0.88 cm
3. A 2.0-cm-tall object is 15 cm from a converging lens of focal length of 13 cm.
1/q = 1/f - 1/p = 1/13 - 1/15
q = 97.5 cm
h' = h * (-(97.5/15)) = -2 * 6.5 = -13 cm
4. A 2.5-cm-tall object is 16 cm from a diverging lens of focal length -13 cm.
1/q = 1/f - 1/p = 1/(-13) - 1/16
q = -7.17 cm
h' = 2.5 * (-(-7.17/16)) = 1.12 cm
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RANKING:
1 > 4 > 2 > 3
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