Part A two point charges are located on the y axis as follows: charge q 1 = -1.0

Question

Part A two point charges are located on the y axis as follows: charge q1 = -1.00nC at y1 = -0.650m , and charge q2 = 3.90nC at the origin (y = 0). What is the magnitude of the net force exerted by these two charges on a third charge q3 = 9.00nC located at y3 = 0.400


Part B What is the direction of the net force

the net force is in +y direction

the net force is in -y direction

the net force is in the + x direction

the net force is in the -x directionm Part A two point charges are located on the y axis as follows: charge q1 = -1.00nC at y1 = -0.650m , and charge q2 = 3.90nC at the origin (y = 0). What is the magnitude of the net force exerted by these two charges on a third charge q3 = 9.00nC located at y3 = 0.400


Part B What is the direction of the net force

the net force is in +y direction

the net force is in -y direction

the net force is in the + x direction

the net force is in the -x directionm

Explanation / Answer

F = F13 +F23

F = kq1q3/1.05^2 + Kq2q3/0.4^2

F = 9*10^9 *9nC*(-1/1.05^2+3/0.4^2)*10^-9

F =1.445*10^-6 N

b. +y direction

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