help Two blocks of masses m1 = 2.00 kg and m2 = 4.25 kg are released from rest a

Question

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Two blocks of masses m1 = 2.00 kg and m2 = 4.25 kg are released from rest at a height of h = 4.40 m on a frictionless track as shown in the figure below. When they meet on the level portion of the track, they undergo a head-on, elastic collision. Determine the maximum heights to which m1 and m2 rise on the curved portion of the track after the collision. hm1 = m hm2 = m Need Help? During a certain time interval, the angular position of a swinging door is described by theta = 5.03 + 10.5t + 1.98t2, where theta is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times. t = 0 theta = rad omega = rad/s alpha = rad/s2 t = 2.91 s theta = rad omega = rad/s alpha = rad/s2 Need Help? A centrifuge in a medical laboratory rotates at an angular speed of 3550 rev/min. When switched off, it rotates 50.0 times before coming to rest. Find the constant angular acceleration of the centrifuge. rad/s2

Explanation / Answer

spped at level position=sqrt(2*9.8*4.4)=9.286 m/s

let speed of m1 after collision be v1 and speed of m2 be v2.

then conserving momentum,

4.25*9.286-2*9.286=2*v1-4.25*v2

conserving kinetic energy,

2*9.826^2+4.25*9.826^2=2*v1^2+4.25*v2^2

solving both the equations,

we get

v1=20.143 m/s

v2=4.563 m/s

so m1 will rise to the height = v1^2/(2*9.8)=20.7 m

m2 will rise=v2^2/(2*9.8)=1.062 m

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