1. calculate the width of the central maximum in the diffraction pattern from th

Question

1. calculate the width of the central maximum in the diffraction pattern from the single slit with width 0.04mm, if the screen were placed 5.00 m away from the slit. Use the accepted wavelength (6328) for the laser light. Proportionalreasoning makes this very easy.

2. if you had used yellow sodium light (wavelength = 5890), what would you have found for the fringe spacing in the interference pattern on a screen 3.00 m away, using the following pairs of double slits?

#of slits 2 2 2 2

Slit width 0.04mm 0.04mm 0.08mm 0.08mm

Slit spacing 0.250mm 0.500mm 0.250mm 0.500mm

Fringe Spacing ? ? ? ?

Fill in the question marks for the "fringe spacing"

Explanation / Answer

Number 1)

y/L = m(wavelength)/a

y/5 = (1)(632.8 X 10^-9)/(4 X 10^-5)

y = .0791 m

The width is twice that value or .1582 m (15.82 cm)

Number 2

Apply y/L = m(wavelength)/d

y/3 = (1)(589 X 10^-9)/(2.5 X 10^-4)

y = 7.068 X 10^-3 m (7.068 mm) for the first set of numbers

For set 2...

y/3 = (1)(589 X 10^-9)/(5 X 10^-4)

y = 3.534 X 10^-3 m (3.534 mm)

For set 3... - Same as set 1, the slit width has nothing to do with double slit interference

y/3 = (1)(589 X 10^-9)/(2.5 X 10^-4)

y = 7.068 X 10^-3 m (7.068 mm)

For set 4... - Same as set 2, the slit width has nothing to do with double slit interference

y/3 = (1)(589 X 10^-9)/(5 X 10^-4)

y = 3.534 X 10^-3 m (3.534 mm)

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