The mechanism below is designed to position pieces of luggage on a ramp. The sui

Question

The mechanism below is designed to position pieces of luggage on a ramp. The suitcase S weighs 20 lb. The mechanism exerts a force on the suitcase in the direction parallel to the ramp. The coefficients of friction between the suitcase and the ramp are ms = 0.20 and mk = 0.18.

(a a) Will the suitcase remain stationary on the ramp when the mechanism exerts no force on it?

(b b) Determine the force the mechanism must exert on the suitcase to start it moving up the ramp.

c) c) Determine the force the mechanism must exert on the suitcase to keep it moving up the ramp once it has started moving

D

Explanation / Answer

a)N = 20 * cos(20) = 18.79 lb...................

Force in down ward direction Fd = 20*sin(20) = 6.84 lb....................

stati cfriction Fs = ms*N = 3.76 lb..........................

Fstatic < Fd....so the suiticase slides down

b) the force needeed to move the suitcase up ward = 6.84 + 3.76 =10.6 lb....................

c) Fnet = 6.84 + mk*N = 10.22 lb.........

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