1 A golf ball of mass 0.047 kg is hit off the tee at a speed of 40.2 m/s. The go

Question

1A golf ball of mass 0.047 kg is hit off the tee at a speed of 40.2 m/s. The golf club was in contact with the ball for 3.29E-3 s. Find the impulse imparted to the golf ball.

Find the average force exerted on the ball by the golf club.

2) A 83.0 kg fullback is running at 3.86 m/s to the east and is stopped in 0.760 s by a head-on tackle by a tackler running due west. Calculate the original momentum of the fullback.

Calculate the impulse exerted on the fullback.

Calculate the impulse exerted on the tackler.

3) A 0.420 kg ice puck, moving east with a speed of 3.12 m/s, has a head-on collision with a 0.890 kg puck initially at rest. Assuming a perfectly elastic collision, what is the speed of the lighter puck? Use east as the positive axis.

Explanation / Answer

a)impule=0.047*40.2=1.8894

force = 1.8894/ 3.29*10^-3=574.29N

2)imomentum=320.38 kgm/s (east is taken as+ve axis)

impulse on fullblack=-320.38kgm/s

impulse on takler=320.38kgm/s

average force =421.55N=320.38/0.76

3)velocity =-1.12m/s

4)v=sqrt(2gh)

v1=sqrt(2*9.8*0.85)=4.08

v2= sqrt(2*9.8*0.67)=3.62

change in momentum =0.65(4.08+3.62)=5.005kgm/s

force =5.005/0.017=294.41N

ke=0.5*0.65*(3.62^2-4.08^2)=-1.15115J

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