2.) The figure show two vectors A and B . Find vector C such that A+B+C=0 . Writ

Question

2.) The figure show two vectors A and B. Find vector C such that A+B+C=0.

Write your answer for C in component form.

Find the magnitude and direction of C.

3.) A particle starts from xo = 10 m at to = 0 s and moves with the velocity graph shown.

Describe what you would see if you were watching this particle as it moved.

Does the particle have a turning point? If so, at what time?

What is the object%u2019s position at t = 3 s?

What is the object%u2019s velocity at t = 3 s?

What is the object%u2019s acceleration at t = 3 s?

Explanation / Answer

A+B=(2cos(20)i+2sin(20)j)+(4cos(40)i-4sin(40)j)=4.94i-1.887j

So

C=-4.94i+1.887j

Mag=5.288

Dir=-20.906 degrees

Particle was de-accelerating from t=0 to t=1 and then accelerating in reverse direction.

Turning point at time t=1s

v=4t-4

So

x=2t^2-4t+c

x(0)=10 so c=10

So

x=2t^2-4t+10

So

x(3)=16m

v(3)=8m/s

a(3)=4m/s^2

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