A point charge Q =-2.9 %u03BC C is placed on a xy plane at the origin of the coo

Question

A point charge Q=-2.9 %u03BCC is placed on a xy plane at the origin of the coordinates as shown in Figure.

(a) Find the electric potential at point A (x=-0.46 m, y=0.25 m).



(b) Find the magnitude and direction of the electric field at point A. For the direction, choose one red arrow in Figure.
Magnitude:  
Direction:   1   2   3   4



(c) How much energy is required to bring a charge of -4.3 %u03BCC from an infinite distance away to point A?


(d) Find the magnitude and direction of the force exerted on the charge at A. Magnitude:  
Direction:   1   2   3   4

Explanation / Answer

(a) r = ( (0.46)^2 + (0.25)^2 )^1/2 = 0.523

q = -2.9*(10^ -6) C

Potential = kq/r = -49904.39 V

(b) Electric field = kq/r^2 = 94419.4

Direction is 4

(c)Energy is change in potential energy

Energy = Potential*q1 = -49904.39 V*-4.3*(10^ -6) = 0.215 J

(d)Force = Electric field*charge = 94419.4*-4.3*(10^ -6) = 0.406 N

Direction is 2

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