1)A 1200 kg car pulls a 480 kg trailer. The car exerts a horizontal force of 354

Question

1)A 1200 kg car pulls a 480 kg trailer. The car exerts a horizontal force of 3540 N against the ground in order to accelerate. What force does the car exert on the trailer? Assume an effective friction coefficient of 0.190 for the trailer.

2) A small ball of mass 117 g is suspended from a fixed point with an ideal string of length 0.75 m.
The ball is given a horizontal push so that it revolves in a circular path.
The angle which the string makes relative to vertical is %u03B8 = 22 degrees.
Calculate the tangential speed with which the ball is traveling to maintain this horizontal path.

Explanation / Answer

friction force = mu.m.g= 1200*9.8*0.190 = 2234.4

So force exerted on trailer = 3540 - friction force = 1305.6N

b) Draw FBD for the ball.

Let tension in string is T

then T sin 22 = mv^2/R

T cos 22 = mg

tan 22 = v^2/Rg

so v= (Rg*tan 22)^0.5 = 1.02 m/s

Here R = 0.75 sin 22

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