question is attached. As shown in the figure below, a green bead of mass 20 g sl
ID: 2113233 • Letter: Q
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question is attached.
As shown in the figure below, a green bead of mass 20 g slides along a straight wire. The length of the wire from point to point is 0.800 m, and point is 0.600 m higher than point . A constant friction force of magnitude 0.010 0 N acts on the bead. If the bead is released from rest at point ,what is its speed at point ? m/s A red bead of mass 20 g slides along a curved wire, subject to a friction force with the same constant magnitude as that on the green bead. If the green and red beads are released simultaneously from rest at point , which bead reaches point with a higher speed? the green bead the red bead both beads arrive with equal speed Explain.Explanation / Answer
mgh - fd = (1/2)mv^2
(20/1000) (9.8) (.6) - (.01) (.8) == (1/2) (20/1000) (v)^2
Solve for v: v = 3.31 m/s^2
The green bead will reach point B at a higher speed because it traveled a shorter distance, and therefore there was a shorter distance for the frictional force to act.
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