1) An electron enter a magnetic field. The magnetic field has a uniform strength

Question

1) An electron enter a magnetic field. The magnetic field has a uniform strength 2.4 T and is oriented at a 45 degree angle to the electron's motion. A force of magnitude 9.2810^-13 N acts on the electron. What is the electron's speed?

a) 9.4*10^6 m/s

b) 8.2*10^5 m/s

c) 5.0*10^6 m/s

d) 3.4*10^6 m/s

2) An alpha particle, which is a helium nucleus, has a mass of 6.64*10^-27 kg. It is travleing horizontally at 42.3 km/s when it enters a uniform, vertical 1.6 T magnetic field. What is the diameter of the path followed by the alpha particle?

a) 0.208 mm

b) 0.878 mm

c) 1.01 mm

d) 0.354 mm

3) An alpha particle, which is a helium nucleus, has a mass of 6.64*10^-27 kg. It is travleing horizontally at 42.3 km/s when it enters a uniform, vertical 1.6 T magnetic field. What is the magnitude of the acceleration of the alpha particle while it is in the magnetic field?

a) 1.06*10^12 m/s^2

b) 7.70*10^12 m/s^2

c) 3.26*10^12 m/s^2

d) 5.49*10^12 m/s^2

Explanation / Answer

1)

speed = 9.28*10^-13/(2.4*sin(45 degrees)*1.6*10^-19) = 3.4*10^6 m/s

2)

diameter = 6.64*10^-27*42300*2/(2*1.6*10^-19*1.6) = 1.1*10^-3 = 1.1mm

3)

acceleration = 1.6*10^-19*2*42300*1.6/(6.64*10^-27) = 3.26*10^12 m/s2

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