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ID: 2111336 • Letter: #
Question
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707px">
Suppose the volume of the syringe is 49 cc. You measure the
pressure as 2.05 atm, and the temperature as 23o
C.
Assume: the diameter of the plunger on the syringe is 2.33
cm.
a)Find
- n, the number of moles of gas in the syringe:
Submissions: in
moles
- N, the number of molecules of gas in the syringe:
Submissions: in
molecules
- Use the molear mass of air given to calculate the mass of air
in
the syringe:
Submissions: in
kg
b)Supose you push down the syringe so the volume is now 39.0
cc,
with the temperature remaining unchanged. Find:
- the new pressure inside the syringe.
Submissions: in
atm
- the force exerted by the gas on the plunger of the
syringe:
Submissions: in
N
Explanation / Answer
a.)PV=nRT
n=PV/RT=2.05*0.049/0.082*296=4.14 x 10^-3 moles
N=6.023x10^23*n=2.49 x 10^21
molar mass of air=28.9645 g/mol
So the mass of air=28.9645*n=0.12 grams
b.)P=nRT/V=4.14x10^-3*0.082*296/0.039=2.58 atm
the diameter of the plunger on the syringe is 2.33
So A=pi*d^2/4=4.26 x 10^-4 m^2
F=P*A=101325*2.58*4.26x10^-4=111.46 N
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