SINGLE SLIT DIFFRACTION: A coherent electromagnetic wave of wavelength 656.3 nm

Question

SINGLE SLIT DIFFRACTION: A coherent electromagnetic wave of wavelength 656.3 nm pusses through a single slit with width a = 0.460 nun. Assume the screen is 1.82 m from the slit. What is the distance from the center of the central maximum to the first minimum (zero) in intensify on screen? What is the distance between the first minimum and the 5th minimum in intensity on screen? From your answer to part (a), what is the width of the central maximum? In this problem, in what range is the electromagnetic wave ? Circle one: x-ray range (ii) visible range (iii) ultra violet range (iv) in the range of radio waves

Explanation / Answer

Part A)

Apply y/L = m(wavelength)/a

y/1.82 = (1)(656.3 X 10^-9)/4.6 X 10^-4)

y = 2.60 X 10^-3 m which is 2.60 mm

Part B)
y/1.82 = (4)(656 X 10^-9)/4.6 X 10^-4)

y = .0104m which is 1.04 cm

Part C)
Width of the central maximum is twice the answer for part a

Width = 5.19 X 10^-3 m which is 5.19 mm

Part D)

This light in in the visible range (Choice ii)

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