A velocity detector in a mass spectrometer has a particle with charge 3x10^-20.

Question

A velocity detector in a mass spectrometer has a particle with charge 3x10^-20. The electron field is 1000 v/m.

v ----->

elect. field |

v in the plane of the page.

a) what is the force exerted by the electric field on the charge?

b) what is the magnitude of the force that the magnetic field must exert on the moving charge to make it go in a straight line?

c) what is the direction of the magnetic field?

d) Assume that the force that the magnetic field exerts on the charge is 3x10^-20 newtons, what will be the mass of the particles that emerge out the right end of the mass spectrograph if the particles travel at 100 meters/second?

Explanation / Answer

A)F=qE=-1.602x10^-19x1000 =-1.602x10^-16 N

b) F=1.602x10^-16 N

c)opposite to electrostatic force

d)3x10^-20=mx100

m=3x10^-22 kg

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