In the figure a compass sits 1.0 cm above a wire in a circuit containing a 1.0 F

Question

In the figure a compass sits 1.0 cm above a wire in a circuit containing a 1.0 F capacitor charged to 4.6 V , a 1.4 O resistor, and an open switch. The compass is lined up with the earth's magnetic field. The switch is closed, so that there is a current in the circuit, and the switch remains closed until the capacitor has completely discharged.

Part A:
What is magnitude of the magnetic field due to the current in the wire right after the switch is closed?
B= ?? T

Part B:
How does this compare with the magnitude of the field of the earth ()?
B/BEarth = ?? %

Part C:

Explanation / Answer

(a)current immediately after closing = 4.6/1.4 = 3.28 A...

Magnetic field due to this current = u0/2pi * i/R = 5.96*10^-5 T....

(b)5.96/5 = 119.22%....

(c) right after the switch is closed, the needle makes 50 degrees with the vertical and slowly comes to its original position.... tan^-1(1.192) = 50

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