45 - The effect of a competitive inhibitor with an enzyme A) causes changes in m

Question

45 - The effect of a competitive inhibitor with an enzyme A) causes changes in maximum velocity only. B) causes changes in K, only C) causes changes in both maximum velocity and K D) can be overcome with low substrate concentration. E) is covalent 9 Refer to the following plot and indicate where each value would be determined. Each option can only be used A and C point to the intercepts on the axes, B and E are the axes themselves and D is the data point on the plot once. 0.1 0.2 0.3 1Ts] 46-The axis where Km would be determined 47-1/Nms 48--1/K 49- The axis where Vmax would be determined S0-Which two values would you need to determine the turnover constant (Kex) of an enzyme? A-kat, Km C-VaR, total enzyme concentration [E], D -substrate concentration [S], Vmax E-IS), [El

Explanation / Answer

Q.45

Ans. B,

Because Competitive inhibitor binds only to Enzyme(E) and not with Enzyme-Substrate complex (ES). So, it interferes with the substrate binding which Increases Km. And as it did not bind with ES, therefore no change in Vmax.

Q. 46-49

This graph is a Double-Reciprocal or Lineweaver-Burk Plot

Ans 46- B (x-axis)

Ans 47- A (1/Vmax)

Ans 48- C (-1/Km)

Ans 49- E (y-axis)

Q. 50

Ans. For the calculation of turnover no. (Kcat), the formula is = Kcat= Vmax/Et

which means, C is the right answer.

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