A barium atom (Z = 56) has two outer electrons in the 6s state when the atom is

Question

A barium atom (Z = 56) has two outer electrons in the 6s state when the atom is on the

ground configuration. A singly charged Ba+ ion is formed when one of the 6s electrons is

removed. The single outer electron of a Ba+ ion is excited into the 6h state (â„“ = 5). Assume this

6h electron is entirely outside the electron cloud of the 54 electrons in the inner shells. What is

the energy of this 6h electron (in eV)? (E1 for hydrogen is −13.6 eV)

(Hint: take into account shielding of the positive nuclear charge by the negative charge of the

inner-shell electrons.)

Explanation / Answer

-13.6ev((1/36)-(1/25))

=-13.6*(-11/36*25)

=.166ev

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