A target glider, whose mass m2 is 310 g , is at rest on an air track, a distance

Question

A target glider, whose mass m2 is 310 g, is at rest on an air track, a distance d = 53 cm from the end of the track. A projectile glider, whose mass m1 is 640 g, approaches the target glider with velocity v1i = -75 cm/s and collides elastically with it (see the figure). The target glider rebounds elastically from a short spring at the end of the track and meets the projectile glider for a second time.

a) How far from the end of the track does this second collision occur ( cm)?

b)How long does the target glider take to reach the end of the track?

c)How much more time elapses before the gliders collide again?

Explanation / Answer

velocity of m1 = v

310*0.75 + 0 = 310* u + 640*v

v-u / 0.75 = 1

so V = 0.489 m/s

u = -0.26 m/s

when m1 is coming in reverse

distance of m2 from wall = 0.53 - 0.26* (0.53/0.489) = 0.248

distcen from wall they meet = 0.489 * (0.248/0.749) = 0.1619 m

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